Django __call__() missing 1 required keyword-only argument: 'manager'

Question

I have two models:

class Someinfo(models.Model):
name = models.CharField(max_length=200)
#something else

class OtherInfo(models.Model):
name2 = models.CharField(max_lenth=200)
related_someinfo = models.ManyToManyField(Someinfo)
#something else

Now I have created CBV views to create and view them. The CreateView works fine and saves info that can be reviewed in admin, but I cannot get the template to display the data on any other view be it FormView, DetailView or any other, because I get this error:

__call__() missing 1 required keyword-only argument: 'manager'

Request Method:     GET
Request URL:    http://something
Django Version:     2.0.3
Exception Type:     TypeError
Exception Value:    

__call__() missing 1 required keyword-only argument: 'manager'

Exception Location:     /usr/local/lib/python3.5/dist-packages/django/forms/forms.py in get_initial_for_field, line 494
Python Executable:  /usr/bin/python3
Python Version:     3.5.3

Checking the line in forms.py it shows that the function that is not working is:

def get_initial_for_field(self, field, field_name):
    """
    Return initial data for field on form. Use initial data from the form
    or the field, in that order. Evaluate callable values.
    """
    value = self.initial.get(field_name, field.initial)
    if callable(value):
        value = value()  # line 494
    return value

Any suggestions? I can query the linked objects via shell and they are saved in the database, so I have no idea how to proceed.

Answer 1

Here is my case, I am using django shell:

python manage.py shell

There are two models: Topic and Entry. I tried to get all entries from Topic which id is 1.

>>> Topic.objects.get(id=1)
<Topic: Chess>
>>> t = Topic.objects.get(id=1)
>>> t.entry_set().all()
Traceback (most recent call last):
  File "<console>", line 1, in <module>
TypeError: __call__() missing 1 required keyword-only argument: 'manager'
>>> t.entry_set.all()
<QuerySet [<Entry: Ah okey, so when testing for a console.log (or oth...>]>
>>> 

The correct command is: t.entry_set.all(), not t.entry_set().all()

Answer 2

use entry_set instead of entry_set()(wihout brackets )