I have a model something like this:
class Task(models.Model):
progress = models.PositiveIntegerField()
estimated_days = models.PositiveIntegerField()
Now I would like to do a calculation Sum(progress * estimated_days)
on the database level. Using Django Aggregation I can have the sum for each field but not the summation of multiplication of fields.
With Django 1.8 and above you can now pass an expression to your aggregate:
from django.db.models import F
Task.objects.aggregate(total=Sum(F('progress') * F('estimated_days')))['total']
Constants are also available, and everything is combinable:
from django.db.models import Value
Task.objects.aggregate(total=Sum('progress') / Value(10))['total']
Update: for Django >= 1.8 please follow the answer provided by @kmmbvnr
it's possible using Django ORM:
here's what you should do:
from django.db.models import Sum
total = ( Task.objects
.filter(your-filter-here)
.aggregate(
total=Sum('progress', field="progress*estimated_days")
)['total']
)
Note: if the two fields are of different types, say integer
& float
, the type you want to return should be passed as the first parameter of Sum
It's a late answer, but I guess it'll help someone looking for the same.
The solution depends on Django version.
django < 1.8
from django.db.models import Sum
MyModel.objects.filter(<filters>).aggregate(Sum('field1', field="field1*field2"))
django >= 1.8
from django.db.models import Sum, F
MyModel.objects.filter(<filters>).aggregate(Sum(F('field1')*F('field2')))
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