Dividing a time.Duration in Golang

Question

At present, the time package in Go has no 'divide' function or anything similar. You can divide a time.Duration by some other value, but it requires a fair bit of casting. Is there any easy/obvious way to divide a time.Duration by something in Go that I'm not seeing? (I know you can divide by a numeric constant, but I need to do it on a dynamic basis.) I'm planning on submitting a issue/feature request to add a basic 'divide' function to the time package, but I wanted to ask here first in case I'm missing some easy way to do this kind of division.

Answer 1

Package time

import "time" 

There is no definition for units of Day or larger to avoid confusion across daylight savings time zone transitions.

To count the number of units in a Duration, divide:

second := time.Second
fmt.Print(int64(second/time.Millisecond)) // prints 1000

To convert an integer number of units to a Duration, multiply:

seconds := 10
fmt.Print(time.Duration(seconds)*time.Second) // prints 10s

const (
        Nanosecond  Duration = 1
        Microsecond          = 1000 * Nanosecond
        Millisecond          = 1000 * Microsecond
        Second               = 1000 * Millisecond
        Minute               = 60 * Second
        Hour                 = 60 * Minute
)

type Duration

A Duration represents the elapsed time between two instants as an int64 nanosecond count. The representation limits the largest representable duration to approximately 290 years.

type Duration int64

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Division and multiplication of time.Duration is described in the Go time package documentation.