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I am trying to calculate p1=(1/1)*(1/2)*...*(1/n) but something is wrong and the printf gives me 0.000...0
#include <stdio.h>
int main(void) {
int i,num;
float p3;
do {
printf ("give number N>3 : \n" );
scanf( "%d", &num );
} while( num <= 3 );
i = 1;
p3 = 1;
do {
p3=p3*(1/i);
printf( "%f\n",p3 );
} while ( i <= num );
printf("\nP3=%f",p3);
return 0;
}
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To divide float values in Python, use the / operator. The Division operator / takes two parameters and returns the float division. Float division produces a floating-point conjecture of the result of a division. If you are working with Python 3 and you need to perform a float division, then use the division operator.
Java does integer division, which basically is the same as regular real division, but you throw away the remainder (or fraction). Thus, 7 / 3 is 2 with a remainder of 1. Throw away the remainder, and the result is 2. Integer division can come in very handy.
Integer division yields an integer result. For example, the expression 7 / 4 evaluates to 1 and the expression 17 / 5 evaluates to 3. C provides the remainder operator, %, which yields the remainder after integer division.
(1/i)
i is an int, so that's integer division, resulting in 0 if i > 1. Use 1.0/i to get floating point division.
51
1 is an integer, i is an integer. So 1/i will be an integer, ie the result will be truncated. To perform floating-point division, one of the operands shall be of type float (or, better, of type double):
p3 *= 1. / i;
I had the same issue. The basic case:
when you want to get float output from two integers, you need to convert one into float
int c = 15;
int b = 8;
printf("result is float %f\n", c / (float) b); // result is float 1.875000
printf("result is float %f\n", (float) c / b); // result is float 1.875000
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