Distinguishing closure and local variables

Question

A local function in the closure declares a variable with the same name which exists in the closure. So, how could we access closure's variable from the local function?

function closure()
{
    var xVar; 
    function func1()
    {
        var xVar;
        // how to distinguish local and closure scopes.
        return xVar;
    }
    return function () { return func1(); };
}

Creating a private object and making private variables as properties of this object could help. But I am wondering if there is a better and neat solution. Can a scope chain help?

I have edited to make it a complete closure. Anyway, closures are not much concern here, it could be considered for inner functions however, there may be a solution with closures somehow.

Thanks

Answer 1

You can't access the scope chain explicitly in JS. Your problem is the age-old one of variable shadowing, but it's that much more maddening because in JS, the scope chain is actually there at runtime, it's just not available for you to access.

You can play some tricks with rejiggering current scope if you use the hated with operator, but that (as well as arguments's caller/callee stuff) really just give you access to objects and functions with their properties. There's no way to say "give me what xVar means in the n-1 runtime scope from right here".