I need to display timestamp of a post with in django template. The timestamp would be like:
"timestamp":1337453263939 in milli seconds
I can convert the timestamp into datetime object and render it in the view. Is there is any direct way to display through the template? The output should be:
print(datetime.datetime.fromtimestamp(1337453263.939))
2012-05-20 00:17:43.939000
{% now "U" %}
The "U"
is a date format for Unix epoch, and can also be used with built-in date
filter. So, if you have the date in a variable:
{{ value|date:"U" }}
You could use custom template filters (see https://docs.djangoproject.com/en/dev/howto/custom-template-tags/). In your case it could like this:
Put into this dir blank file "__init__.py" and "timetags.py" with code:
from django import template
import datetime
register = template.Library()
def print_timestamp(timestamp):
try:
#assume, that timestamp is given in seconds with decimal point
ts = float(timestamp)
except ValueError:
return None
return datetime.datetime.fromtimestamp(ts)
register.filter(print_timestamp)
In your template, add
{% load timetags %}
Use following syntax in template:
{{ timestamp|print_timestamp }}
Where timestamp = 1337453263.939 from your example
This will print timestamp in local date and time format. If you want to customize output, you can modify print_timestamp in following way:
import time
def print_timestamp(timestamp):
...
#specify format here
return time.strftime("%Y-%m-%d %H:%M:%S", time.gmtime(ts))
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