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I want to display the Mysql table Filed values in selectbox. I tried the following code to display. But it normally display the specified field values in echo function and not in select box. I don't know where I mistake.
$con = mysql_connect("localhost","root","root");
$db = mysql_select_db("Time_sheet",$con);
$get=mysql_query("SELECT Emp_id FROM Employee");
while($row = mysql_fetch_assoc($get))
{
echo ($row['Emp_id']."<br/>");
}
<html>
<body>
<form>
<select>
<option value = "<?php echo($row['Emp_id'])?>" ><?php echo($row['Emp_id']) ?></option>
</select>
</form>
</body>
</html>
Also the field values must be display in ascending order. How to achieve..
596
<?php
$con = mysql_connect("localhost","root","root");
$db = mysql_select_db("Time_sheet",$con);
$get=mysql_query("SELECT Emp_id FROM Employee ORDER BY Emp_id ASC");
$option = '';
while($row = mysql_fetch_assoc($get))
{
$option .= '<option value = "'.$row['Emp_id'].'">'.$row['Emp_id'].'</option>';
}
?>
<html>
<body>
<form>
<select>
<?php echo $option; ?>
</select>
</form>
</body>
</html>
PS : On a sidenote, please stop using mysql_* functions. Take a look at this thread for the reasons.
53
You can easily do it like this
$con = mysql_connect("localhost","root","root");
$db = mysql_select_db("Time_sheet",$con);
$get=mysql_query("SELECT Emp_id FROM Employee");
<html>
<body>
<form>
<select>
<option value="0">Please Select</option>
<?php
while($row = mysql_fetch_assoc($get))
{
?>
<option value = "<?php echo($row['Emp_id'])?>" >
<?php echo($row['Emp_id']) ?>
</option>
<?php
}
?>
</select>
</form>
</body>
</html>
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