Display match found or not using awk

Question

i have a scenario where i have three words in a file called demo.txt

My three words are : apple , mango , grapes

i want to write a one linear command to check if all three word exist in a file then display match found successfully or otherwise display match not found

how to do with awk command in one linear way

below is my code not working

awk '{print (/apple/|/mango/|/grapes/ ? "true : match found " : "false : not found ")}' /D/demo.txt

sample file : demo.txt

abc:apple
b:mango
fgg:grapes
ball , candle 
vik,mani
raj,vilas

apart from first file **i have second file which contain below text

Azr
hjkds
$$ABC=%wkde**mo
$Bilas=%ram 
xyz
vxbnx
ram 

I want to check whether the exact keyword present or not $$ABC=%wkde**mo $Bilas=%ram

if match found display message keyword found or otherwise display keyword not found

Answer 1

Could you please try following. In case your awk supports word boundaries.

awk '
/\<apple\>/{
  app_found=1
}
/\<mango\>/{
  mango_found=1
}
/\<grapes\>/{
  grapes_found=1
}
END{
  if(app_found && mango_found && grapes_found){
    print "All 3 words found."
  }
  else{
    print "All 3 words are NOT present in whole Input_file."
  }
}
' Input_file

Answer 2

Edited answer: the following command has been tested with the input sample provided above and works as desired:

awk '
  BEGIN { RS = "§" }
  {print (/apple/ && /mango/&&/grapes/) ? "match found" : "match not found"}
' demo.txt

I used the char § as record separator because there is no such a char in the input and because RS = "\0" is not portable. If you feel it could happen that such a § could occur in the input file, you can use the portable solution below:

awk '
  { i = i $0 } 
  END { print (i ~ /apple/ && i ~ /mango/ && i ~ /grapes/) ? "match found" : "match not found"}
' demo.txt