Display loading image while post with ajax

Question

Let's say you have a tag someplace on the page which contains your loading message:

<div id='loadingmessage' style='display:none'>
  <img src='loadinggraphic.gif'/>
</div>

You can add two lines to your ajax call:

function getData(p){
    var page=p;
    $('#loadingmessage').show();  // show the loading message.
    $.ajax({
        url: "loadData.php?id=<? echo $id; ?>",
        type: "POST",
        cache: false,
        data: "&page="+ page,
        success : function(html){
            $(".content").html(html);
            $('#loadingmessage').hide(); // hide the loading message
        }
    });

Take a look at ajaxStart and ajaxStop

$.ajax(
{
    type: 'post',
    url: 'mail.php',
    data: form.serialize(),
    beforeSend: function()
    {
        $('.content').html('loading...');
    },
    success: function(data)
    {
        $('.content').html(data);
    },
    error: function()
    {
        $('.content').html('error');
    }
});

have fun playing arround!

if you should have quick loading times which prevent te loading showing, you can add a timeout of some sort.

This is very simple and easily manage.

jQuery(document).ready(function(){
jQuery("#search").click(function(){
    jQuery("#loader").show("slow");
    jQuery("#response_result").hide("slow");
    jQuery.post(siteurl+"/ajax.php?q="passyourdata, function(response){
        setTimeout("finishAjax('response_result', '"+escape(response)+"')", 850);
            });
});

})
function finishAjax(id,response){ 
      jQuery("#loader").hide("slow");   
      jQuery('#response_result').html(unescape(response));
      jQuery("#"+id).show("slow");      
      return true;
}

<div id="load" style="display:none"><img src="ajax-loader.gif"/></div>

function getData(p){
        var page=p;
        document.getElementById("load").style.display = "block";  // show the loading message.
        $.ajax({
            url: "loadData.php?id=<? echo $id; ?>",
            type: "POST",
            cache: false,
            data: "&page="+ page,
            success : function(html){
                $(".content").html(html);
        document.getElementById("load").style.display = "none";
            }
        });