How can I drop or disable the indices in a pandas Data Frame?
I am learning the pandas from the book "python for data analysis" and I already know I can use the dataframe.drop to drop one column or one row. But I did not find anything about disabling the all the indices in place.
Remove Index of a Pandas DataFrame Using the reset_index() Method. The pandas. DataFrame. reset_index() method will reset the index of the DataFrame to the default index.
The most straightforward way to drop a Pandas dataframe index is to use the Pandas . reset_index() method. By default, the method will only reset the index, forcing values from 0 - len(df)-1 as the index. The method will also simply insert the dataframe index into a column in the dataframe.
Dealing with index and axis If you want the concatenation to ignore existing indices, you can set the argument ignore_index=True . Then, the resulting DataFrame index will be labeled with 0 , …, n-1 . To concatenate DataFrames horizontally along the axis 1 , you can set the argument axis=1 .
df.values
gives you the raw NumPy ndarray
without the indexes.
>>> df x y 0 4 GE 1 1 RE 2 1 AE 3 4 CD >>> df.values array([[4, 'GE'], [1, 'RE'], [1, 'AE'], [4, 'CD']], dtype=object)
You cannot have a DataFrame without the indexes, they are the whole point of the DataFrame :)
But just to be clear, this operation is not inplace:
>>> df.values is df.values False
DataFrame keeps the data in two dimensional arrays grouped by type, so when you want the whole data frame it will have to find the LCD of all the dtypes and construct a 2D array of that type.
To instantiate a new data frame with the values from the old one, just pass the old DataFrame to the new ones constructor and no data will be copied the same data structures will be reused:
>>> df1 = pd.DataFrame([[1, 2], [3, 4]]) >>> df2 = pd.DataFrame(df1) >>> df2.iloc[0,0] = 42 >>> df1 0 1 0 42 2 1 3 4
But you can explicitly specify the copy
parameter:
>>> df1 = pd.DataFrame([[1, 2], [3, 4]]) >>> df2 = pd.DataFrame(df1, copy=True) >>> df2.iloc[0,0] = 42 >>> df1 0 1 0 1 2 1 3 4
d.index = range(len(d))
does a simple in-place index reset - i.e. it removes all of the existing indices, and adds a basic integer one, which is the most basic index type a pandas Dataframe can have.
Additionally, if you are using the df.to_excel
function of a pd.ExcelWriter
, which is where it is written to an Excel worksheet, you can specify index=False
in your parameters there.
create the Excel writer:
writer = pd.ExcelWriter(type_box + '-rules_output-' + date_string + '.xlsx',engine='xlsxwriter')
We have a list called lines
:
# create a dataframe called 'df'
df = pd.DataFrame([sub.split(",") for sub in lines], columns=["Rule", "Device", "Status"]))
#convert df to Excel worksheet
df.to_excel(writer, sheet_name='all_status',**index=False**)
writer.save()
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