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Directions API total distance & duration with waypoints

I am getting directions including waypoints from Directions API in my Android app. It contains multiple "leg" segments which has its own distance and duration. Is there a way to sum all distances and durations get the total values?

Example: Stripped json segment from Direction API

legs": [
{
  "distance": {
    "text": "389 km",
    "value": 389438
  },
  "duration": {
   "text": "6 hours 31 mins",
   "value": 23452
  }
},
{
  "distance": {
   "text": "0.5 km",
   "value": 487
  },
  "duration": {
   "text": "2 mins",
   "value": 102
  }
}
]

from the above response, is there a way to calculate and show the output like following:

Total distance: 389.5 km Total duration: 6 hours 33 mins

like image 434
Much Overflow Avatar asked Dec 19 '22 04:12

Much Overflow


2 Answers

As addition to my comment and answer of @Kushal here is a way how to calculate total time. I skip the way to get JSONObject, because it described already and give an example with given String[] which you get while parsing JSON. In this example I made ALL of possible scenarios with given response, so you may use it without modifying:

    String[] timeItems = {"4 days 1 hour 12 mins", "5 hours 9 mins"}; // as example for visibility
    int[] total = {0, 0, 0}; // days, hours, minutes
    for(int i = 0; i < timeItems.length; i++){
        if(timeItems[i].contains("day ")){
            total[0]++;
        }else if(timeItems[i].contains("days")){
            total[0] += Integer.valueOf(timeItems[i].substring(0, timeItems[i].indexOf(" days")));
        }
        if(timeItems[i].contains("hour ")){
            total[1]++;
        }else if(timeItems[i].contains("hours")){
            if(timeItems[i].indexOf(" hours") <= 3){
                total[1] += Integer.valueOf(timeItems[i].substring(0, timeItems[i].indexOf(" hours")));
            }else{
                if(timeItems[i].contains("days")){
                    total[1] += Integer.valueOf(timeItems[i].substring(timeItems[i].lastIndexOf("days ")) + 5, timeItems[i].indexOf(" hours"));
                }else{
                    total[1] += Integer.valueOf(timeItems[i].substring(timeItems[i].lastIndexOf("day ")) + 4, timeItems[i].indexOf(" hours"));
                }
            }
        }
        if(timeItems[i].contains("min ")){
            total[2]++;
        }else if(timeItems[i].contains("mins")){
            if(timeItems[i].indexOf(" mins") <= 3){
                total[2] += Integer.valueOf(timeItems[i].substring(0, timeItems[i].indexOf(" mins")));
            }else{
                if(timeItems[i].contains("hours")){
                    total[2] += Integer.valueOf(timeItems[i].substring(timeItems[i].indexOf("hours ") + 6, timeItems[i].indexOf(" mins")));
                }else{
                    total[2] += Integer.valueOf(timeItems[i].substring(timeItems[i].indexOf("hour ") + 5, timeItems[i].indexOf(" mins")));
                }
            }
        }
    }
    Log.d("LOG", total[0] + " days " + total[1] + " hours " + total[2] + " mins.");

This got to be a little bit more complex than I thought, maybe it is possible to simplify somehow or use similar ideas, but the main point is to show you working example. I debugged this code. It gives correct output:

05-19 23:00:38.687  14251-14251/whatever.com.myapplication D/LOG﹕ 4 days 6 hours 21 mins.

I hope this is helpful. Let me know if it either fits you or not.

like image 153
Yurets Avatar answered Dec 26 '22 00:12

Yurets


This adds duration to Kushal's answer:

public void parseJson(String json) {

    JSONObject jsonObj = new JSONObject(json);
    JSONObject object = (JSONObject) new JSONTokener(json).nextValue();

    JSONObject legsJson = object.getJSONObject("legs");
    long totalDistance = 0;
    int totalSeconds = 0;
    for( int i = 0; i < legsJson.size(); i++ ) {
        // distance in meter
        totalDistance = totalDistance + Long.parseLong(jsonObj[i].getJSONArray("distance").getString("value"));
        totalSeconds = totalSeconds + Integer.parseInt(jsonObj[i].getJSONArray("duration").getString("value"));
    }

    // convert to kilometer
    double dist = dist / 1000.0 ;
    Log.d("distance", "Calculated distance:" + dist);

    int days = totalSeconds / 86400
    int hours = (totalSeconds - days * 86400) / 3600;
    int minutes = (totalSeconds - days * 86400 - hours * 3600) / 60;
    int seconds = totalSeconds - days * 86400 - hours * 3600 - minutes * 60;
    Log.d("duration", days + " days " + hours + " hours " + minutes + " mins" + seconds + " seconds");
}
like image 44
Elias N Avatar answered Dec 25 '22 23:12

Elias N