different behaviour of println() in java

Question

//take the input from user
text = br.readLine();

//convert to char array
char ary[] = text.toCharArray();


System.out.println("initial string is:" + text.toCharArray());

System.out.println(text.toCharArray());

Output:

initial string is:[C@5603f377
abcd

Answer 1

println() is overloaded to print an array of characters as a string, which is why the 2nd print statement works correctly:

public void println(char[] x)

Prints an array of characters and then terminate the line. This method behaves as though it invokes print(char[]) and then println().

Parameters:
x - an array of chars to print.

The 1st println() statement, on the other hand, concatenates the array's toString() with another string. Since arrays don't override toString(), they default to Object's implementation, which is what you see.