A random class definition:
class ABC:
x = 6
Setting some values, first for the abc instance, later for the static variable:
abc = ABC()
abc.x = 2
ABC.x = 5
and then print the results:
print abc.x
print ABC.x
which prints
2
5
Now, I don't really get what is going on, because if i replace in the class definition x = 6 for "pass", it will just output the same thing. My question is, what is the purpose of defining a variable in the class definition in python if it seems like i can anyone set at any time any variable without doing so?
Also, does python know the difference between instance and static variables? From what I saw, I'd say so.
Yes, definitely possible to write static variables and methods in python. Static Variables : Variable declared at class level are called static variable which can be accessed directly using class name.
Instance variables are created when an object is created with the use of the keyword 'new' and destroyed when the object is destroyed. Static variables are created when the program starts and destroyed when the program stops. Instance variables can be accessed directly by calling the variable name inside the class.
Python Instance Variables. Python instance variables are owned by an instance of a class. The value of an instance variable can be different depending on the instance with which the variable is associated. This means that the value of each instance variable can be.
static variable are class variables and its not specific to any instance. Simply we can say its common for all the instance of the class. Whenever changed the static values from one instance of the class that modified value is visible to all other instances of the class.
Warning: the following is an oversimplification; I'm ignoring __new__()
and a bunch of other special class methods, and handwaving a lot of details. But this explanation will get you pretty far in Python.
When you create an instance of a class in Python, like calling ABC() in your example:
abc = ABC()
Python creates a new empty object and sets its class to ABC. Then it calls the __init__()
if there is one. Finally it returns the object.
When you ask for an attribute of an object, first it looks in the instance. If it doesn't find it, it looks in the instance's class. Then in the base class(es) and so on. If it never finds anybody with the attribute defined, it throws an exception.
When you assign to an attribute of an object, it creates that attribute if the object doesn't already have one. Then it sets the attribute to that value. If the object already had an attribute with that name, it drops the reference to the old value and takes a reference to the new one.
These rules make the behavior you observe easy to predict. After this line:
abc = ABC()
only the ABC object (the class) has an attribute named x. The abc instance doesn't have its own x yet, so if you ask for one you're going to get the value of ABC.x. But then you reassign the attribute x on both the class and the object. And when you subsequently examine those attributes you observe the values you put there are still there.
Now you should be able to predict what this code does:
class ABC:
x = 6
a = ABC()
ABC.xyz = 5
print(ABC.xyz, a.xyz)
Yes: it prints two fives. You might have expected it to throw an AttributeError exception. But Python finds the attribute in the class--even though it was added after the instance was created.
This behavior can really get you in to trouble. One classic beginner mistake in Python:
class ABC:
x = []
a = ABC()
a.x.append(1)
b = ABC()
print(b.x)
That will print [1]. All instances of ABC() are sharing the same list. What you probably wanted was this:
class ABC:
def __init__(self):
self.x = []
a = ABC()
a.x.append(1)
b = ABC()
print(b.x)
That will print an empty list as you expect.
To answer your exact questions:
My question is, what is the purpose of defining a variable in the class definition in python if it seems like i can anyone set at any time any variable without doing so?
I assume this means "why should I assign members inside the class, instead of inside the __init__
method?"
As a practical matter, this means the instances don't have their own copy of the attribute (or at least not yet). This means the instances are smaller; it also means accessing the attribute is slower. It also means the instances all share the same value for that attribute, which in the case of mutable objects may or may not be what you want. Finally, assignments here mean that the value is an attribute of the class, and that's the most straightforward way to set attributes on the class.
As a purely stylistic matter it's shorter code, as you don't have all those instances of self. all over. Beyond that it doesn't make much difference. However, assigning attributes in the __init__
method ensures they are unambiguously instance variables.
I'm not terribly consistent myself. The only thing I'm sure to do is assign all the mutable objects that I don't want shared in the __init__
method.
Also, does python know the difference between instance and static variables? From what I saw, I'd say so.
Python classes don't have class static variables like C++ does. There are only attributes: attributes of the class object, and attributes of the instance object. And if you ask for an attribute, and the instance doesn't have it, you'll get the attribute from the class.
The closest approximation of a class static variable in Python would be a hidden module attribute, like so:
_x = 3
class ABC:
def method(self):
global _x
# ...
It's not part of the class per se. But this is a common Python idiom.
class SomeClass:
x=6 # class variable
def __init__(self):
self.y = 666 # instance variable
There is virtue in declaring a class scoped variable: it serves as default for one. Think of class scoped variable as you would think of "static" variables in some other languages.
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