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Both std::is_signed<T> and std::numeric_limits<T>::is_signed are supposed to give answers about the signedness of T.
Why are there now two indicators for signedness (i.e. since C++11)?
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std::numeric_limits ::digits in C++ with Example The std::numeric_limits ::digits function is used to find the number of radix digits that the data type can represent without loss of precision. Header File: #include<limits>
Data types that supports std::numeric_limits() in C++ std::numeric_limits<int>::max() gives the maximum possible value we can store in type int. std::numeric_limits<unsigned int>::max()) gives the maximum possible value we can store in type unsigned int.
I'm going to hazard a guess that the only difference is if std::numeric_limits<T> is specialized for a user-defined type. Such a user-defined type could of course provide their own value for is_signed. But asking for std::is_signed<T>::value on this type will always return false unless std::is_signed<T> has been independently specialized.
It seems as though the condition that std::is_signed<T> represents is
is_arithmetic<T>::value && T(-1) < T(0)
Update: The always-knowledgable Howard Hinnant points out that while std::numeric_limits<> can be legally-specialized, nothing in <type_traits> is allowed to be specialized unless otherwise specified, and is_signed is not specified as being specializable.
Therefore, std::numeric_limits<T>::is_signed may return true for a user-defined type (if it's been specialized) but std::is_signed<T>::value will always return false for user-defined types.
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