Difference between int * array and int array[] in a function parameter

Question

I have seen that the array values ​​will change if the function parameter is "int arr[]" or "int * arr". Where is the difference?

int array[]:

void myFunction(int arr[], int size) {

    for (int i = 0; i < size; ++i)
        arr[i] = 1;
}

int * array:

void myFunction(int * arr, int size) {

    for (int i = 0; i < size; ++i)
        arr[i] = 1;
}

Both functions change the array values.

int main(){

     int array[3];

     array[0] = 0;
     array[1] = 0;
     array[2] = 0;

     myFunction(array, 3);

     return 0;

 }

Answer 1

There is no difference. Both functions types (after adjustment) are "function taking a pointer to int and an int, returning void." This is just a syntactic quirk of C++: the outermost [] in a function parameter of non-reference type is synonymous with *.