Difference between Force Unwrapping Optionals and Implicitly Unwrapped Optionals

Question

I was very confused about forced unwrapping and implicit unwrapping at first. Now, the following understanding comes from my self-study:

There is no action available for implicit unwrapping, but there is something called implicitly unwrapped Optionals. Implicitly unwrapped Optionals and normal Optionals are both Optionals, the difference being when accessing an implicitly unwrapped Optional, you confidently know that there is a valid value under the hood and ready for use. Normal Optionals need if let binding or a forced unwrapping (!) action to access the possible values behind the optional variables.

Summary:

Forced unwrapping is an action done on the normal Optionals.

Implicitly unwrapped Optionals are Optionals, usually used for class initialization and will pass values without exclamation mark when used.

Question:

Am I right? If my understanding is not precise, I would appreciate it if you correct me.

Thanks

Answer 1

First of all let's define an Optional

An Optional value is a container of some type (Int, String, UIColor, ...), it could contain the value (1, "Hello world", .greenColor(), ...) or nil.

let anOptionalInt: Int? = 1 let anotherOptionalInt: Int? = nil 

When in Swift we see an Optional value we think:

Ok this could contain the actual value or nil

Force unwrapping

It's the action of extracting the value contained inside an Optional. This operation is dangerous because you are telling the compiler: I am sure this Optional value does contain a real value, extract it!

let anOptionalInt: Int? = 1 let anInt: Int = anOptionalInt! 

Now anInt contains the value 1.

If we perform a force unwrapping on an Optional value that happens to contain nil we get a fatalError, the app does crash and there is no way to recover it.

let anotherOptionalInt: Int? = nil let anotherInt = anotherOptionalInt!  fatal error: unexpectedly found nil while unwrapping an Optional value 

Implicitly unwrapped optionals

When we define an Implicitly unwrapped optional, we define a container that will automatically perform a force unwrap each time we read it.

var text: String! = "Hello" 

If now we read text

let name = text 

we don't get an Optional String but a plain String because text automatically unwrapped it's content.

However text is still an optional so we can put a nil value inside it

text = nil 

But as soon as we read it (and it contains nil) we get a fatal error because we are unwrapping an optional containing nil

let anotherName = text  fatal error: unexpectedly found nil while unwrapping an Optional value 

Answer 2

An implicitly unwrapped optional is a normal optional behind the scenes, but can also be used like a non optional value, so yes you are correct.

But if you declare a value as implicitly unwrapped, it is equivalent to force unwrapping it at every use.

For Implicitly unwrapped Optionals there are 4 main reasons to do that.

1: A Constant That Cannot Be Defined During Initialization

2: Interacting with an Objective-C API

3: When Your App Cannot Recover From a Variable Being nil

4: NSObject Initializers