Determining if an Object is of primitive type

Question

The types in an Object[] will never really be primitive - because you've got references! Here the type of i is int whereas the type of the object referenced by o is Integer (due to auto-boxing).

It sounds like you need to find out whether the type is a "wrapper for primitive". I don't think there's anything built into the standard libraries for this, but it's easy to code up:

import java.util.*;

public class Test
{
    public static void main(String[] args)        
    {
        System.out.println(isWrapperType(String.class));
        System.out.println(isWrapperType(Integer.class));
    }

    private static final Set<Class<?>> WRAPPER_TYPES = getWrapperTypes();

    public static boolean isWrapperType(Class<?> clazz)
    {
        return WRAPPER_TYPES.contains(clazz);
    }

    private static Set<Class<?>> getWrapperTypes()
    {
        Set<Class<?>> ret = new HashSet<Class<?>>();
        ret.add(Boolean.class);
        ret.add(Character.class);
        ret.add(Byte.class);
        ret.add(Short.class);
        ret.add(Integer.class);
        ret.add(Long.class);
        ret.add(Float.class);
        ret.add(Double.class);
        ret.add(Void.class);
        return ret;
    }
}

commons-lang ClassUtils has relevant methods.

The new version has:

boolean isPrimitiveOrWrapped = 
    ClassUtils.isPrimitiveOrWrapper(object.getClass());

The old versions have wrapperToPrimitive(clazz) method, which will return the primitive correspondence.

boolean isPrimitiveOrWrapped = 
    clazz.isPrimitive() || ClassUtils.wrapperToPrimitive(clazz) != null;

Google's Guava library has a Primitives utility that check if a class is a wrapper type for a primitive: Primitives.isWrapperType(class).

Class.isPrimitive() works for primitives

For those who like terse code.

private static final Set<Class> WRAPPER_TYPES = new HashSet(Arrays.asList(
    Boolean.class, Character.class, Byte.class, Short.class, Integer.class, Long.class, Float.class, Double.class, Void.class));
public static boolean isWrapperType(Class clazz) {
    return WRAPPER_TYPES.contains(clazz);
}

Starting in Java 1.5 and up, there is a new feature called auto-boxing. The compiler does this itself. When it sees an opportunity, it converts a primitive type into its appropriate wrapper class.

What is probably happening here is when you declare

Object o = i;

The compiler will compile this statement as saying

Object o = Integer.valueOf(i);

This is auto-boxing. This would explain the output you are receiving. This page from the Java 1.5 spec explains auto-boxing more in detail.

I think this happens due to auto-boxing.

int i = 3;
Object o = i;
o.getClass().getName(); // prints Integer

You may implement a utility method that matches these specific boxing classes and gives you if a certain class is primitive.

public static boolean isWrapperType(Class<?> clazz) {
    return clazz.equals(Boolean.class) || 
        clazz.equals(Integer.class) ||
        clazz.equals(Character.class) ||
        clazz.equals(Byte.class) ||
        clazz.equals(Short.class) ||
        clazz.equals(Double.class) ||
        clazz.equals(Long.class) ||
        clazz.equals(Float.class);
}

Integer is not a primitive, Class.isPrimitive() is not lying.