Determine where a function was executed?

Question

how should I define a function, where,which can tell where it was executed, with no arguments passed in? all files in ~/app/

a.py:

def where():
    return 'the file name where the function was executed'

b.py:

from a import where
if __name__ == '__main__':
    print where() # I want where() to return '~/app/b.py' like __file__ in b.py

c.py:

from a import where
if __name__ == '__main__':
    print where() # I want where() to return '~/app/c.py' like __file__ in c.py

Answer 1

You need to look up the call stack by using inspect.stack():

from inspect import stack

def where():
    caller_frame = stack()[1]
    return caller_frame[0].f_globals.get('__file__', None)

or even:

def where():
    caller_frame = stack()[1]
    return caller_frame[1]