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Given a java.lang.reflect.Method object, is there anyway to determine whether the method is purely functional (i.e., given the same input, it will always produce the same output and it is stateless. In other words, the function does not depend on its environment)?
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No. Just being static does not make a function pure. In purely functional programming the outcome of the function should depend only on their arguments, regardless of global state. Static functions can easily access and modify global state.
A static method (or static function) is a method defined as a member of an object but is accessible directly from an API object's constructor, rather than from an object instance created via the constructor.
You should consider making a method static in Java : 1) If a method doesn't modify the state of the object, or not using any instance variables. 2) You want to call the method without creating an instance of that class.
Like a mathematical function, a Java static method can take on more than one argument, and therefore can have more than one parameter variable.
No, there's no way to do it.
Reflection does not allow you to inspect the actual code behind the method.
And even if that where possible, the actual analysis would probably be ... tricky, to say the least.
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No there is no way to do that with reflection or any other mechanism.
The developer knows if the method is functional. For example, Spring has a @Cacheable annotation that gives a hint to the application that the method is functional and can therefore cache the result for a given set of arguments. (Spring will wrap your object in a proxy that provides the caching behavior.)
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