Determine if a JavaScript function is a bound function

Question

Is there a way to determine if a JavaScript function is a bound function?

Example:

var obj = {    x:1    };    function printX() {      document.write(this.x);  }    function takesACallback(cb) {    // how can one determine if this is a bounded function    // not just a function?    if (typeof cb === 'function') {      cb();      }  }    takesACallback(printX.bind(obj)); // 1  takesACallback(printX);           // undefined

Perhaps this is an important point. I am not asking why the second call prints undefined.

Answer 1

Both bound functions and arrow functions do not have a prototype property:

typeof (function() {}).prototype // 'object' as usual typeof (function() {}).bind(null).prototype // 'undefined'! typeof (() => {}).prototype // 'undefined'! 

This is not 100% safe since you could still manually assign this property (although that'd be weird).
As such, a simple way to check for bindability would be the following:

// ES5 function isBindable(func) {   return func.hasOwnProperty('prototype'); }  // ES6 const isBindable = func => func.hasOwnProperty('prototype'); 

Usage:

isBindable(function () {}); // true isBindable(() => {}); // false isBindable(   (function () {}).bind(null) ); // false 

This way you can make sure that the function that has been passed can deal with a dynamic this.

Here is an example usage for which the above fails:

const arrowFunc = () => {}; arrowFunc.prototype = 42;  isBindable(arrowFunc); // true :( 

---

Interestingly, while bound functions do not have a prototype property they can still be used as constructors (with new):

var Animal = function(name) {    this.name = name; };  Animal.prototype.getName = function() {   return this.name; };  var squirrel = new Animal('squirrel'); console.log(squirrel.getName()); // prints "squirrel"  var MutatedAnimal = Animal.bind({}); // Radiation :) console.log(MutatedAnimal.hasOwnProperty('prototype')); // prints "false"  var mutatedSquirrel = new MutatedAnimal('squirrel with two heads'); console.log(mutatedSquirrel.getName()); // prints "squirrel with two heads" 

In that case, the original function prototype (Animal) is used instead.
See JS Bin, code and link courtesy of Dmitri Pavlutin.

This of course won't work with arrow functions since they can't be used as constructors.

Unfortunately, I don't know if there is a way to distinguish a bound function (usable as constructor) from an arrow function (not usable as constructor) without trying them out with new and checking if it throws (new (() => {}) throws a "is not a constructor" error).

Answer 2

In environments that support ES6, you can check whether the name of the function starts with "bound " (the word "bound" followed by a space).

From the spec:

19.2.3.2 Function.prototype.bind ( thisArg , ...args)

[...]

15. Perform SetFunctionName(F, targetName, "bound").

Of course that could result in false positives if the name of the function was manually changed.