I am trying to determine groups in a string.
For example "AAABBCCCCD" should have ["AAA", "BB", "CCCC", "D"] as groups based on the pattern in the string.
Here is my simple function to do that:
const patternGroup = (str) => {
let cursor = str[0]
let groups = []
let currentGroup = ""
for (let i = 0; i < str.length; i++) {
let ch = str[i]
if (ch === cursor) {
currentGroup += ch
}
else {
groups.push(currentGroup)
currentGroup = ch
cursor = ch
}
}
if (currentGroup !== "") {
groups.push(currentGroup)
}
return groups
}
It works as intented but I am looking for a simpler function, maybe using map/reduce or regex. Any ideas?
string[] strArr = strFood . GroupBy(y => Char. IsDigit(y)). Select(y => y.
Capturing groups are a way to treat multiple characters as a single unit. They are created by placing the characters to be grouped inside a set of parentheses. For example, the regular expression (dog) creates a single group containing the letters "d", "o", and "g".
Regular expressions allow us to not just match text but also to extract information for further processing. This is done by defining groups of characters and capturing them using the special parentheses ( and ) metacharacters. Any subpattern inside a pair of parentheses will be captured as a group.
Groups group multiple patterns as a whole, and capturing groups provide extra submatch information when using a regular expression pattern to match against a string. Backreferences refer to a previously captured group in the same regular expression.
Formally, each group is such that a word is in the group if and only if it is similar to at least one other word in the group. We are given a list strs of strings where every string in strs is an anagram of every other string in strs.
839. Similar String Groups Two strings X and Y are similar if we can swap two letters (in different positions) of X, so that it equals Y. Also two strings X and Y are similar if they are equal.
The group (String string) method of Matcher Class is used to get the group of the match result already done, from the specified string. Parameters: This method takes a parameter string which is the String from which the group index of the matched pattern is required.
You can count the number of groups in the current match using the groupCount () method of the Matcher class. This method calculates the number of capturing groups in the current match and returns it.
you can simply use RegExp:
var input = "AAABBCCCCD";
const res = input.match(/([^])(\1*)/g);
console.log(res)
Similar to your implementation:
const patternGroupWithReduce = (str) => {
let currentGroup = ""
return str.split("").reduce((acc, cur, i) => {
currentGroup += cur
if (str[i + 1] !== cur) {
acc.push(currentGroup)
currentGroup = ""
}
return acc
}, [])
}
const patternGroupWithRegex = (str) => {
return str.match(/(.)\1*/g)
}
RegEx /(.)\1/g* uses the back reference for the capturing group.
\1* matches the same char as recently captured one as many times as possible.
Here is the visualization for it:
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