How can I detect whether an input element such as the following is currently focused within a ReactJS render function?
<input type="text" style={searchBoxStyle} placeholder="Search"></input>
Syntax: var ele = document. activeElement; Return value: It returns the currently focused element in the document.
To focus input when another element is clicked in React: Set the ref prop on the input element. Set the onClick prop on the other element. When the other element is clicked, focus the input, e.g. ref.
To check when the focus is lost in a React Native TextInput, we can set the onBlur prop to a function that runs when focus is lost. to set the onBlur prop to a function that logs 'focus lost' when we move focus away from the text input.
If you just want to make autofocus in React, it's simple. While if you just want to know where to put that code, answer is in componentDidMount(). In most cases, you can attach a ref to the DOM node and avoid using findDOMNode at all.
You can check against document.activeElement
as long as the input node is mounted and there is a reference to it:
const searchInput = React.useRef(null) if (document.activeElement === searchInput.current) { // do something } return <input type="text" ref={searchInput} />
Another way would be to add event listeners for the focus
and blur
events inside the input field:
const [focused, setFocused] = React.useState(false) const onFocus = () => setFocused(true) const onBlur = () => setFocused(false) return <input type="text" onFocus={onFocus} onBlur={onBlur} />
Note that this will call a re-render each time the node is focused or blurred (but this is what you want, right?)
I started with the answer given by David, where he describes two methods, and they both worked for me, but I had concerns about both:
On the first case it uses findDOMNode
, what has some disadvantages: at minimum its use is discouraged, and it can easily be implemented in a way that it is considered an anti-pattern; and also it can make the code slower, by bypassing the virtual DOM and working with the DOM directly.
On the second option, create and manage a component state only to find that answer seems too much work, can easily get out of sync, and can cause the component to re-render unnecessarily.
So after trying to explore the issue more, I came up with the following solution:
if (this.props.id === document.activeElement.id) { // your code goes here }
The same comment on David's answer applies:
You should not do this in the
render
method though, because the input node might not be mounted yet. Use a lifecycle method likecomponentDidUpdate
orcomponentDidMount
.
Advantages:
Requirements:
id
property that is passed to the form element you want to check (which is most likely the case anyway)If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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