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Detect in-app browser (WebView) with PHP / Javascript

I developed an app for iOS and Android which accesses an HTML file from my webserver using the in-app browser (Webview).

I don't want that a user can access this file without using the app. Is there a possibility to detect, if the user is accessing the file with the app or directly via a browser on this smartphone / tablet / computer? I think that a solution with PHP is much better, because Javascript can be switched off. At least Google Analytics can differentiate between Safari and Safari (in-app). It should work with every version of iOS and Android.

Thanks for your help.


Solution

After many attempts I finally found a working solution for me!

iOS: You can detect the difference between Safari and the in-app browser using the user agent. Probably there's a nicer solution, but it works.

// Safari (in-app)
if ((strpos($_SERVER['HTTP_USER_AGENT'], 'Mobile/') !== false) && (strpos($_SERVER['HTTP_USER_AGENT'], 'Safari/') == false) {
    echo 'Safari (in-app)';
}

Android: The package name from the app is stored in the PHP variable $_SERVER['HTTP_X_REQUESTED_WITH'].

// Android (in-app)
if($_SERVER['HTTP_X_REQUESTED_WITH'] == "com.company.app") {
    echo 'Android (in-app)';
}

As Tim van Elsloo already noted HTTP headers can be faked and this is not absolutely secure.

like image 577
ohh2ahh Avatar asked May 05 '13 10:05

ohh2ahh


2 Answers

I'm not sure about Android, but when you're using the iOS SDK's UIWebView, it sends the name and version of your app as part of the user agent (YourApp/1.0).

You can then use PHP to check if your in-app webview is being used or not:

if (strpos($_SERVER['HTTP_USER_AGENT'], 'YourApp/') !== false)

I think Android does something similar as well.

like image 87
cutsoy Avatar answered Nov 16 '22 00:11

cutsoy


Solution code:

$isWebView = false;
if((strpos($_SERVER['HTTP_USER_AGENT'], 'Mobile/') !== false) && (strpos($_SERVER['HTTP_USER_AGENT'], 'Safari/') == false)) :
    $isWebView = true;
elseif(isset($_SERVER['HTTP_X_REQUESTED_WITH'])) :
    $isWebView = true;
endif;

if(!$isWebView) : 
    // Android or iOS Webview
else :
    // Normal Browser
endif;
like image 8
Alex Baur Avatar answered Nov 16 '22 00:11

Alex Baur