I have an image that I want to have trigger certain behaviors when the mouse is over, I have a mouseover and mouseout method, but if you happen to have your mouse over the image when the page loads, the mouseover method never fires until you leave the image and come back over it.
Is there a way to detect if the mouse is over an element on the fly without the mouse having to be off of the element and then come over the element to trigger the JS mouseover event? Like is there a document.getElementById("blah").mouseIsOver() type function in Javascript?
I believe this is possible without any action from the user. When your page loads, bind the mouseover
event to your image and hide your image (i.e. using CSS display:none
). Use setTimeout()
to show it again in a few milliseconds (10 should be enough). The even should be fired.
If you don't want to cause the 'flick' effect on your image, you may try using some temporary element instead, attaching event to it, and delegating the event onto your image.
I have no idea if this is cross-browser solution, but it worked from my Firefox 3.0 console ;)
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