How to know that user has clicked outside our react app which is pointed to
<div id="root">
(I'm having extra space to click outside root div)
I've tried the below code
import ReactDOM from 'react-dom';
// ... ✂
componentDidMount() {
document.addEventListener('click', this.handleClickOutside, true);
}
componentWillUnmount() {
document.removeEventListener('click', this.handleClickOutside, true);
}
handleClickOutside = event => {
const domNode = ReactDOM.findDOMNode(this);
if (!domNode || !domNode.contains(event.target)) {
this.setState({
visible: false
});
console.log("clicked outside")
}
}
But then, even if I clicked inside some child popup component under parent, it is showing as "clicked outside"
If I click anywhere inside the app (including children component), it should not say, "clicked outside"
So is there any way to know that the user clicked outside the complete app itself?
The easiest way is to set a listener to the application container (the outmost element in the tree), instead of finding the id="root" element.
So, with given index.html:
<div id="root"></div>
<div>Div which outside of app</div>
Possible implementation can be (check the logs):
function useOnClickOutside(ref, handler) {
useEffect(() => {
const listener = event => {
if (!ref.current || ref.current.contains(event.target)) {
return;
}
handler(event);
};
document.addEventListener("mousedown", listener);
document.addEventListener("touchstart", listener);
return () => {
document.removeEventListener("mousedown", listener);
document.removeEventListener("touchstart", listener);
};
}, [ref, handler]);
}
const App = () => {
const divRef = useRef();
const handler = useCallback(() => console.log(`Click Outside`), []);
useOnClickOutside(divRef, handler);
return (
<div
ref={divRef}
style={{
margin: `0.5rem`,
padding: `1rem`,
border: `2px solid black`,
cursor: `pointer`
}}
>
Application
</div>
);
};
ReactDOM.render(
<React.StrictMode>
<App />
</React.StrictMode>,
document.getElementById("root")
);
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