In the javascript Event
object, there are some boolean values to check if modifier keys are pressed:
ctrlKey
: CTRL key.altKey
: ALT key.altLeft
: ALT left key. Only for IE.altGraphKey
: ALTGR key. Only for Chrome/Safari.However, there are some issues:
ctrlKey
to true
and altKey
to true
when you press the ALTGR modifier.ctrlKey
to false
and altKey
to true
when you press the ALTGR modifier, as only ALT has been pressed.altGraphKey
property, but it is always undefined
.Question: how can I difference between an ALT+CTRL or an ALTGR key press? Specially in Chrome.
Just like how you use the Control key for Ctrl + C, you can use ALT GR + key which also houses the special or the accented letter. Windows allows emulating Alt GR when you press Ctrl + Alt keys together.
Ctrl + Alt + F11 sort of puts the GUI to sleep, and puts you into a virtual terminal mode, something like the old fashion ttys. Once in this mode you can choose between 6 different tty input screens.
The altGraphKey in webkit browsers no longer appears to exist (as at September 2013) and the behaviour of Firefox has changed. Browser behaviours for the AltGr key currently appear to be:
Which is to say, they are all currently consistent (apart from IE8, which remains consistently inconsistent).
The following snippet should catch Alt Gr - but not Alt or Ctrl - in modern browsers. You will need a special case for IE8 however:
if (event.ctrlKey && event.altKey) {
// Appears to be Alt Gr
}
Disclaimer: I don't have a keyboard that has this key, so I can't test myself, but the spec says that can use the key
property. This may be a good solution if you only need to support browsers that implement it (at time of writing, only Safari doesn't). You can check if the value is "AltGraph"
.
window.onkeydown = function (e) {
if (e.key === 'AltGraph') {
console.log(e.key);
}
};
Worth mentioning is that it is possible to detect this in modern browser by checking the location of the alt key event.
See: Is there a way to detect which side the Alt key was pressed on (right or left)?
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