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In a matrix, to remove the columns in which the element of the first line is 0, we can use:
ind2remove = (A(1,:) == 0);
A(:,ind2remove) = [];
How do I do that if A is a cell? I want to remove the columns in which the element of the first row is 0.
I tried:
ind2remove = (A{1,:} == 0);
A{:,ind2remove} = [];
but I got the error message:
??? Error using ==> eq
Too many input arguments.
Error in ==> ind2remove = (A{1,:} == 0);
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The easiest way to remove a row or column from a matrix is to set that row or column equal to a pair of empty square brackets [] . For example, create a 4-by-4 matrix and remove the second row.
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Description: The percent sign is most commonly used to indicate nonexecutable text within the body of a program. This text is normally used to include comments in your code. Some functions also interpret the percent sign as a conversion specifier.
Indexing using { } gives you the contents of the cell, whereas indexing using ( ) returns the same type as the original object i.e., if A is a cell, A{i,j} will return what it's holding, and A(i,j) will always return a cell. You need the latter.
So in your case, you can do the following to eliminate all columns where the first row has a 0.
A(:, cellfun(@(x)x==0, A(1,:))) = [];
The assumption here is that each cell in the first row holds only a single numeric element, as per your comment.
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