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Deleting DOM elements before the Page is displayed to the screen (in a Chrome extension)

I am trying to create an extension that will get rid of certain Page elements (by id or class) before the page is displayed to the screen. I've tried using an event listener on the document with "DOMContentLoaded" as the event but the javascript seems to execute after the page is displayed to the user and then deletes it so it's not as smooth as I want (not showing the unwanted content at all)

document.addEventListener("DOMContentLoaded", function() {

var elements = document.getElementsByClassName("header-nav-item");
while(elements.length > 0){
    elements[0].parentNode.removeChild(elements[0]);
}

var element = document.getElementById("topchapter");
element.parentNode.removeChild(element);
element = document.getElementById("wrapper_header");
    element.parentNode.removeChild(element);

});

This is the content script that my extension uses which deletes after the page is loaded. What do I need to use to modify the DOM before the pages is seen by the user?

like image 424
irregular Avatar asked Sep 11 '15 23:09

irregular


1 Answers

Use MutationObserver in the content script injected at document_start to actually delete the HTML elements from DOM during page load before they are rendered so that there's no flickering.

  • manifest.json:
{
  "name": "Delete elements",
  "version": "1.0",
  "content_scripts": [
    {
      "matches": ["*://somesite.com/*"],
      "run_at": "document_start",
      "all_frames": true,
      "js": ["content.js"]
    }
  ],
  "manifest_version": 2
}
  • content.js:
const DEL_SELECTOR = '.header-nav-item, #topchapter, #wrapper_header';

const mo = new MutationObserver(onMutation);
// in case the content script was injected after the page is partially loaded
onMutation([{addedNodes: [document.documentElement]}]);
observe();

function onMutation(mutations) {
  let stopped;
  for (const {addedNodes} of mutations) {
    for (const n of addedNodes) {
      if (n.tagName) {
        if (n.matches(DEL_SELECTOR)) {
          stopped = true;
          mo.disconnect();
          n.remove();
        } else if (n.firstElementChild && n.querySelector(DEL_SELECTOR)) {
          stopped = true;
          mo.disconnect();
          for (const el of n.querySelectorAll(DEL_SELECTOR)) el.remove();
        }
      }
    }
  }
  if (stopped) observe();
}

function observe() {
  mo.observe(document, {
    subtree: true,
    childList: true,
  });
}

Notes:

  • The observer callback must be simple and fast in order not to introduce lags during page loading so use simple selectors and direct DOM access instead of jQuery.
  • When the job is done it's best to disconnect the observer immediately so that the rest of the page isn't needlessly observed.
  • Don't add multiple observers, incorporate all checks in just one
  • mutations array also contains text subnodes along with the added elements themselves. That's why we make sure tagName is present - it means the node is an element.
  • Each mutation's addedNodes array usually has container elements like DIV, for example, which in turn may have an element we want to delete inside. So we have to examine it with querySelector or querySelectorAll.
  • childNode.remove() works since Chrome 23
like image 59
wOxxOm Avatar answered Oct 20 '22 16:10

wOxxOm