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I want to delete elements from array A that may be found in array B.
For example:
A = numpy.array([1, 5, 17, 28, 5])
B = numpy.array([3, 5])
C = numpy.delete(A, B)
C= [1, 17, 28]
605
You can use unset() function which removes the element from an array and then use array_values() function which indexes the array numerically.
Array elements can be deleted using the JavaScript operator delete . Using delete leaves undefined holes in the array. Use pop() or shift() instead.
Find the index of the array element you want to remove using indexOf , and then remove that index with splice . The splice() method changes the contents of an array by removing existing elements and/or adding new elements. The second parameter of splice is the number of elements to remove.
Numpy has a function for that :
numpy.setdiff1d(A, B)
That will give you a new array with the result you expect.
More info on the sciPy documentation
151
You can try :
list(set(A)-set(B))
#[1, 28, 17]
Or a list comprehension :
[a for a in A if a not in B]
Another solution :
import numpy
A[~numpy.isin(A, B)]
#array([ 1, 17, 28])
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