Menu
I may be going about this the wrong way, but I'm trying define and fill arrays within a loop.
for i = 0,39 do begin
xx = long(findgen(n+1l)*sx + line1x[i])
sz = size(xx)
arrayname = 'line' + strtrim(i,2)
arrayname = findgen(3,sz[1])
arrayname[0,*] = xx
arrayname[1,*] = yy
arrayname[2,*] = vertline
endfor
This obviously won't work, but is there a way to use the string defined by 'line' + strtrim(i,2) to create and fill a new array upon each iteration? In this case I'd have 40 arrays with names line0...39. The difficult part here is that sz[1] varies, so I can't simply define one large array to hold everything.
841
You can loop through the array elements with the for loop, and use the length property to specify how many times the loop should run.
Each time the for loop runs, it has a different value – and this is the case with arrays. A for loop examines and iterates over every element the array contains in a fast, effective, and more controllable way. This is much more effective than printing each value individually: console.
We can use iteration with a for loop to visit each element of an array. This is called traversing the array. Just start the index at 0 and loop while the index is less than the length of the array.
In idl 8.0 or later you could use the HASH datatype for this.
Your code would looks like this:
array_dict = hash()
for ii = 0,39 do begin
xx = long(findgen(n+1l)*sx + line1x[ii])
sz = size(xx)
arrayname = 'line' + string(1, FORMAT='(i02)')
array = findgen(3,sz[1])
array[0,*] = xx
array[1,*] = yy
array[2,*] = vertline
array_dict[arrayname] = array
endfor
You can now access your arrays by name:
line = array_dict['line01']
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
