Declaring a python function with an array parameters and passing an array argument to the function call?

Question

I am a complete newbie to python and attempting to pass an array as an argument to a python function that declares a list/array as the parameter.

I am sure I am declaring it wrong,

here goes:

def dosomething(listparam):          #do something here dosomething(listargument) 

Clearly this is not working, what am I doing wrong?

Thanks

Answer 1

What you have is on the right track.

def dosomething( thelist ):     for element in thelist:         print element  dosomething( ['1','2','3'] ) alist = ['red','green','blue'] dosomething( alist )   

Produces the output:

1 2 3 red green blue 

A couple of things to note given your comment above: unlike in C-family languages, you often don't need to bother with tracking the index while iterating over a list, unless the index itself is important. If you really do need the index, though, you can use enumerate(list) to get index,element pairs, rather than doing the x in range(len(thelist)) dance.

Answer 2

Maybe you want to unpack elements of an array, I don't know if I got it, but below an example:

def my_func(*args):     for a in args:         print(a)  my_func(*[1,2,3,4]) my_list = ['a','b','c'] my_func(*my_list)