Declaring a prototype of type "struct" - C

Question

I've been racking my brains on this for a while, I'm simply trying to create a method that returns a struct as I wish to return two int's.

My prototype for the method is as follows:

typedef struct RollDice();

Also the method itself:

typedef struct RollDice()
{
 diceData diceRoll;

 diceRoll.dice1 = 0;
 diceRoll.dice2 = 0;

 return diceRoll;
}

The compiler shows the error: "Syntax error: ')'" for both the prototype and actual method.

The struct itself:

typedef struct
{
 int dice1;
 int dice2;
}diceData;

Is it obvious where I'm going wrong? I've tried everything I can think of.

Thanks

Edit/Solution:

To get the program to work with the suggested solutions I had to make the following changes to the struct,

typedef struct diceData
    {
     int dice1;
     int dice2;
    };

Answer 1

You'll want typedef struct ... diceData to occur before your function, and then the signature of the function will be diceData RollDice().

typedef <ORIGTYPE> <NEWALIAS> means that whenever <NEWALIAS> occurs, treat it as though it means <ORIGTYPE>. So in the case of what you've written, you are telling the compiler that struct RollDice is the original type (and of course, there is no such struct defined); and then it sees () where it was expecting a new alias.