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Is it possible to declare a number in Python as
a = 35_000
a = 35,000
Neither seem to work of course. How do you emphasize things like these, for clarity in Python? Is it possible?
952
The pythonic way Similarly for python, "digit" is in base 2³⁰ which means it will range from 0 to 2³⁰ - 1 = 1073741823 of the decimal system.
maxsize is 2**31-1 on a 32-bit environment and 2**63-1 on a 64-bit environment, like sys. maxint in Python2. Converted to binary and hexadecimal numbers with bin() and hex() , sys.
Type int(x) to convert x to a plain integer. Type long(x) to convert x to a long integer.
In the approach above we assume that 999999 is the maximum possible value in our list and compare it with other elements to update when a value lesser than it is found.
This is actually just now possible in Python 3.6.
You can use the first format that you showed:
a = 35_000
because underscores are now an accepted separator in numbers. (You could even say a = 3_5_00_0, though why would you?)
The second method you showed will actually create a tuple. It's the same as saying:
a = (35, 000) # Which is also the same as (35, 0).
Yes, this is possible starting with python 3.6.
PEP 515 adds the ability to use underscores in numeric literals for improved readability. For example:
>>> 1_000_000_000_000_000 1000000000000000 >>> 0x_FF_FF_FF_FF 4294967295
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