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How can I declare a list of objects in php as a private instance variable?
In Java the declaration would look something like this
private ArrayList<Object> ls
and the constructor would have this
ls = new ArrayList<Object>();
Thanks
669
Syntax to create an empty array: At this time, $emptyArray contains “first”, with this command and sending “first” to the array which is declared empty at starting. In other words, the initialization of new array is faster, use syntax var first = [] rather while using syntax var first = new Array().
The object is declared to use the properties of a class. The object variable is declared by using the new keyword followed by the class name. Multiple object variables can be declared for a class.
Each variable or object in an array is called an element. Unlike stricter languages, such as Java, you can store a mixture of data types in a single array. For example, you could have array with the following four elements: an integer, a window object, a string and a button object.
An array is a data structure that stores one or more similar type of values in a single value. For example if you want to store 100 numbers then instead of defining 100 variables its easy to define an array of 100 length.
PHP allocates memory dynamically and what's more, it doesn't care what sort of object you store in your array.
If you want to declare your array before you use it something along these lines would work:
var $myArray = array();
Then you can store any object you like in your variable $myArray. Many people find this a strange concept to grasp after working in a strict language like java.
109
you can declare it in class like
private $array = array();
and append objects (or anything) to that array like
$array[] = some object
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