Decimal.Round default setting for MidpointRounding [duplicate]

Question

The following applies:

var rounded = Decimal.Round(7.635m, 2); //rounded: 7.63 

This, to me, is wrong and unexpected behavior. I would assume the value of rounded to be 7.64.

To achieve this, I can do:

var rounded = Decimal.Round(7.635m, 2, MidpointRounding.AwayFromZero); //rounded: 7.64 

How can this not be the default behavior of Decimal.Round? Any good reason for this?

Answer 1

How can this not be the default behavior of Decimal.Round? Any good reason for this?

If you look at the documentation of Decimal.Round Method (Decimal)

The behavior of this method follows IEEE Standard 754, section 4. This kind of rounding is sometimes called round half to even or banker's rounding. It minimizes rounding errors that result from consistently rounding a midpoint value in a single direction. It is equivalent to calling the Round(Decimal, MidpointRounding) method with a mode argument of MidpointRounding.ToEven.