decimal to 8 bit binary conversion in c++

Question

I am working on decimal to binary conversion. I can convert them, using char bin_x [10]; itoa (x,bin_x,2); but the problem is, i want answer in 8 bits. And it gives me as, for example x =5, so output will be 101, but i want 00000101. Is there any way to append zeros in the start of array? or is it possible to get answer in 8 bits straight away? I am doing this in C++

Answer 1

In C++, the easiest way is probably to use a std::bitset:

#include <iostream>
#include <bitset>

int main() { 
    int x = 5;

    std::bitset<8> bin_x(x);
    std::cout << bin_x;

    return 0;
}

Result:

00000101