My approach:
An array of fixed-length (lets say 20) each element is pointer to the first node of a linked list. so i have 20 different linked list.
This is the structure:
struct node{
char data[16];
struct node *next;
};
My declaration for that array
struct node *nodesArr[20];
now to add a new node to one of the linked list, i do this:
struct node *temp;
temp = nodesArr[i]; // i is declared and its less than 20
addNode(temp,word); // word is declared (char *word) and has a value ("hello")
The addNode function:
void addNode(struct node *q, char *d){
if(q == NULL)
q = malloc(sizeof(struct node));
else{
while(q->next != NULL)
q = q->next;
q->next = malloc(sizeof(struct node));
q = q->next;
}
q->data = d; // this must done using strncpy
q->next = NULL;
}
and to print data from the array of linked list, i do this:
void print(){
int i;
struct node *temp;
for(i=0 ; i < 20; i++){
temp = nodesArr[i];
while(temp != NULL){
printf("%s\n",temp->data);
temp = temp->next;
}
}
}
now compiler gives no error, the program run and i pass the data to it, and when i call print it doesn't print any thing,,??
UPDATE::
after I edited the code (thx for you), i think the problem in the print function,, any idea ?
The problem lies in addNode()
. When the list is empty you do:
q = malloc(sizeof(struct node));
but the scope of q
is limited to addNode()
. You should have declared addNode()
as
void addNode(struct node **q, char *d)
and adjust your code accordingly:
*q = malloc(sizeof(struct node));
and so on...
When you pass struct node *q
to addNode
you are giving it an address for an element in your array. If you use malloc
inside, then you are overwriting this variable q
, which is local to the function and now points to something different, but you haven't changed your original array. Try using a pointer to pointer to node (struct node **q
).
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