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2 FEB is the 33rd day of the year, for example.
Is there a built-in T-SQL function that returns the day-of-year (in SQL Server 2000)? Or do you have to roll your own using casts to get the first day of the year for the supplied date, and then do a DateDiff?
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The DAYOFYEAR function returns an integer, in the range of 1 to 366, that represents the day of the year, where 1 is January 1. The schema is SYSIBM. The argument must be an expression that returns a value of one of the following built-in data types: a date, a timestamp, a character string, or a graphic string.
SQL Server DATEADD() Function The DATEADD() function adds a time/date interval to a date and then returns the date.
If you want to get a day from a date in a table, use the SQL Server DAY() function. This function takes only one argument – the date. This can be a date or date and time data type. (In our example, the column VisitDate is of the date data type.)
MySQL WEEKDAY() Function The WEEKDAY() function returns the weekday number for a given date. Note: 0 = Monday, 1 = Tuesday, 2 = Wednesday, 3 = Thursday, 4 = Friday, 5 = Saturday, 6 = Sunday.
SELECT datepart(dayofyear, getdate())
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