DateTimeFormatter Support for Single Digit Day of Month and Month of Year

Question

DateTimeFormmater doesn't seem to handle single digit day of the month:

String format = "MM/dd/yyyy";
String date   = "5/3/1969";
System.out.println(new SimpleDateFormat(format).parse(date));
System.out.println(LocalDate.parse(date, DateTimeFormatter.ofPattern(format)));

In this example, SimpleDateFormat correctly parses the date, but DateTimeFormatter throws an exception. If I were to use zero padded dates, e.g., "05/03/1969", both work. However, if either the day of month or the month of year are single digit, then DateTimeFormatter throws an exception.

What is the right DateTimeFormatter format to parse both one and two digit day of month and month of year?

Answer 1

From the documentation:

Number: If the count of letters is one, then the value is output using the minimum number of digits and without padding.

So the format specifier you want is M/d/yyyy, using single letter forms. Of course, it will still parse date Strings like "12/30/1969" correctly as for these day/month values, two digits are the “minimum number of digits”.

The important difference is that MM and dd require zero padding, not that M and d can’t handle values greater than 9 (that would be a bit… unusual).

Answer 2

In Java 8 Date Time API, I recently used

DateTimeFormatter formatter = new DateTimeFormatterBuilder()             .appendOptional(DateTimeFormatter.ofPattern("M/dd/yyyy"))             .toFormatter();  System.out.println(LocalDate.parse("10/22/2020", formatter)); System.out.println(LocalDate.parse("2/21/2020", formatter)); 

Answer 3

The best approach to deal with this kind of problem , That is number of different digits in Date (in day , month or year ) is to use this pattern : (M/d/[uuuu][uu]) .

Example:

String date = "7/7/2021"; // or "07/07/2021" or "07/7/21" etc
LocalDate localDate = LocalDate.parse(
date,DateTimeFormatter.ofPattern("M/d/[uuuu][uu]"));

Here uuuu/uu handle four and two digits year.