DataTable with dropdown Column

Question

I need to make dropdown as column in DataTable jQuery it is lookinng like as below right now

And I want it like the below image

and the code which I use is

<table id="example" class="hover row-border dataTable" role="grid" width="100%">
    <thead class="dataTableHeader">
        <tr>
            <th>Days</th>
            <th>Start Time</th>
            <th>End Time</th>
        </tr>
    </thead>
</table>

$(document).ready(function () {
    $('#example').DataTable({
        "aaData": OrganizationData.OrganizationPreference.ScheduleDaysCol,
        "columns": [
            {"data": "DayName"},
            {"data": "StartDateHour"},
            {"data": "EndDateHour"}

        ],
        "paging": false,
        "ordering": false,
        "info": false,
        "filter": false
    });
});

Answer 1

Another way would be to use the render method:

        "render": function(d,t,r){
            var $select = $("<select></select>", {
                "id": r[0]+"start",
                "value": d
            });
            $.each(times, function(k,v){
                var $option = $("<option></option>", {
                    "text": v,
                    "value": v
                });
                if(d === v){
                    $option.attr("selected", "selected")
                }
                $select.append($option);
            });
            return $select.prop("outerHTML");
        }

Working example.

Answer 2

You can use this way then for the dropdown setting

 "aaData": OrganizationData.OrganizationPreference.ScheduleDaysCol,
                        "columnDefs": [{ "targets": 0,"data": "DayName" },
                            {
                            "targets": 1,
                            "data": "StartDateTime",
                           "render": function (data, type, full, meta) {
                                    var $select = $("<select></select>", {
                                    });
                                    $.each(times, function (k, v) {

                                        var $option = $("<option></option>", {
                                            "text": v,
                                            "value": v
                                        });
                                        if (data === v) {
                                            $option.attr("selected", "selected")
                                        }
                                        $select.append($option);
                                    });
                                    return $select.prop("outerHTML");
                            }