I am designing a sql db for business listings in my local area. I am using mySQL WorkBench to design the DB, how ever I am having some issues with one of the tables in the DB not being able to be created.
This is what the db design looks like
The issue I am having is with BusinessHours, I am finding it abit confusing because I want to relate it with a Foregin key to BusinessDirectory (each businessDirectory has many BusinessHours) 'one to many' so that you can represent the 7 days of the week. Hope that makes sense.
This is the sql generated using mySQL workbench
SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES';
CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET utf8 COLLATE utf8_general_ci ;
USE `mydb` ;
-- -----------------------------------------------------
-- Table `mydb`.`Members`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `mydb`.`Members` ;
CREATE TABLE IF NOT EXISTS `mydb`.`Members` (
`idMembers` INT NOT NULL AUTO_INCREMENT ,
`firstName` VARCHAR(45) NOT NULL ,
`lastName` VARCHAR(45) NOT NULL ,
`email` VARCHAR(45) NOT NULL ,
`password` VARCHAR(45) NOT NULL ,
PRIMARY KEY (`idMembers`) )
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `mydb`.`BusinessDirectory`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `mydb`.`BusinessDirectory` ;
CREATE TABLE IF NOT EXISTS `mydb`.`BusinessDirectory` (
`idBusinessDirectory` INT NOT NULL ,
`businessName` VARCHAR(45) NOT NULL ,
`businessDescription` VARCHAR(1000) NULL ,
`businessLogo` VARCHAR(45) NULL ,
`idMembers` INT NULL ,
`directoryCategory` VARCHAR(45) NULL ,
PRIMARY KEY (`idBusinessDirectory`) ,
INDEX `idMembers_idx` (`idMembers` ASC) ,
CONSTRAINT `idMembers`
FOREIGN KEY (`idMembers` )
REFERENCES `mydb`.`Members` (`idMembers` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `mydb`.`BusinessAddress`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `mydb`.`BusinessAddress` ;
CREATE TABLE IF NOT EXISTS `mydb`.`BusinessAddress` (
`idBusinessDirectory` INT NOT NULL ,
`addressNumber` VARCHAR(5) NULL ,
`addressAreaName` VARCHAR(45) NULL ,
`addressLat` FLOAT(10,6) NULL ,
`addressLong` FLOAT(10,6) NULL ,
PRIMARY KEY (`idBusinessDirectory`) ,
CONSTRAINT `idBusinessDirectory`
FOREIGN KEY (`idBusinessDirectory` )
REFERENCES `mydb`.`BusinessDirectory` (`idBusinessDirectory` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `mydb`.`BusinessHours`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `mydb`.`BusinessHours` ;
CREATE TABLE IF NOT EXISTS `mydb`.`BusinessHours` (
`idBusinessDirectory` INT NOT NULL ,
`dayOfWeek` INT NULL ,
`openingTime` TIME NULL ,
`closingTime` TIME NULL ,
PRIMARY KEY (`idBusinessDirectory`) ,
CONSTRAINT `idBusinessDirectory`
FOREIGN KEY (`idBusinessDirectory` )
REFERENCES `mydb`.`BusinessDirectory` (`idBusinessDirectory` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
USE `mydb` ;
SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;
So I was hoping that someone can help me figure out why I am unable to add BusinessHours table to my db.
Here are two screenshots showing the error msgs I am reciving in phpMyAdmin
any help would be appreciated
Final Updated sql;
SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES';
CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET utf8 COLLATE utf8_general_ci ;
USE `mydb` ;
-- -----------------------------------------------------
-- Table `mydb`.`Members`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `mydb`.`Members` ;
CREATE TABLE IF NOT EXISTS `mydb`.`Members` (
`idMembers` INT NOT NULL AUTO_INCREMENT ,
`firstName` VARCHAR(45) NOT NULL ,
`lastName` VARCHAR(45) NOT NULL ,
`email` VARCHAR(45) NOT NULL ,
`password` VARCHAR(45) NOT NULL ,
PRIMARY KEY (`idMembers`) )
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `mydb`.`BusinessDirectory`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `mydb`.`BusinessDirectory` ;
CREATE TABLE IF NOT EXISTS `mydb`.`BusinessDirectory` (
`idBusinessDirectory` INT NOT NULL ,
`businessName` VARCHAR(45) NOT NULL ,
`businessDescription` VARCHAR(1000) NULL ,
`businessLogo` VARCHAR(45) NULL ,
`idMembers` INT NULL ,
`directoryCategory` VARCHAR(45) NULL ,
PRIMARY KEY (`idBusinessDirectory`) ,
INDEX `idMembers_idx` (`idMembers` ASC) ,
CONSTRAINT `idMembers`
FOREIGN KEY (`idMembers` )
REFERENCES `mydb`.`Members` (`idMembers` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `mydb`.`BusinessAddress`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `mydb`.`BusinessAddress` ;
CREATE TABLE IF NOT EXISTS `mydb`.`BusinessAddress` (
`idBusinessDirectory_BusinessAddress` INT NOT NULL ,
`addressNumber` VARCHAR(5) NULL ,
`addressAreaName` VARCHAR(45) NULL ,
`addressLat` FLOAT(10,6) NULL ,
`addressLong` FLOAT(10,6) NULL ,
PRIMARY KEY (`idBusinessDirectory_BusinessAddress`) ,
CONSTRAINT `idBusinessDirectory_BusinessAddress`
FOREIGN KEY (`idBusinessDirectory_BusinessAddress` )
REFERENCES `mydb`.`BusinessDirectory` (`idBusinessDirectory` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `mydb`.`BusinessHours`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `mydb`.`BusinessHours` ;
CREATE TABLE IF NOT EXISTS `mydb`.`BusinessHours` (
`idBusinessDirectory_BusinessHours` INT NOT NULL ,
`dayOfWeek` INT NULL ,
`openingTime` TIME NULL ,
`closingTime` TIME NULL ,
PRIMARY KEY (`idBusinessDirectory_BusinessHours`) ,
CONSTRAINT `idBusinessDirectory_BusinessHours`
FOREIGN KEY (`idBusinessDirectory_BusinessHours` )
REFERENCES `mydb`.`BusinessDirectory` (`idBusinessDirectory` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
USE `mydb` ;
SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;
this is what the Foregin key tab should look like
thanks for the help guys
The constraint name idBusinessDirectory
for foreign key is repeated in table BusinessHours
and BusinessAddress
.
Give different name to the constraint.
UPDATED
Follow a proper FK naming convention so that such error never pops up and just by the name of constraint we can know the tables involved in the constraint.
fk_[referencing table name]_[referenced table name]_[referencing field name]
So in your case the constraints will be
EDIT Update your code with this
BusinessAddress Table
CONSTRAINT `fk_BusinessAddress_BusinessDirectory_idBusinessDirectory`
FOREIGN KEY (`idBusinessDirectory` )
REFERENCES `mydb`.`BusinessDirectory` (`idBusinessDirectory` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
BusinessHours Table
CONSTRAINT `fk_BusinessHours_BusinessDirectory_idBusinessDirectory`
FOREIGN KEY (`idBusinessDirectory` )
REFERENCES `mydb`.`BusinessDirectory` (`idBusinessDirectory` )
ON DELETE NO ACTION
ON UPDATE NO ACTION)
All your constraints are stored in this INFORMATION_SCHEMA.KEY_COLUMN_USAGE
in INNODB
REFER
Hope it helps.
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