I have a connection string that looks like this
con_str = "myuser/[email protected]:1521/ora1"
Where ora1
is the SID of my database. Using this information in SQL Developer works fine, meaning that I can connect and query without problems.
However, if I attempt to connect to Oracle using this string, it fails.
cx_Oracle.connect(con_str) DatabaseError: ORA-12514: TNS:listener does not currently know of service requested in connect descriptor
This connection string format works if the ora1
is a service name, though.
I have seen other questions that seem to have the reverse of my problem (it works with SID, but not Service name)
What is the proper way to connect to Oracle, using cx_Oracle
, using an SID
and not a service name? How do I do this without the need to adjust the TNSNAMES.ORA
file? My application is distributed to many users internally and making changes to the TNSNAMES
file is less than ideal when dealing with users without administrator privileges on their Windows machines. Additionally, when I use service name, I don't need to touch this file at all and would like it keep it that way.
SERVICE_NAMES specifies one or more names by which clients can connect to the instance. The instance registers its service names with the listener. When a client requests a service, the listener determines which instances offer the requested service and routes the client to the appropriate instance.
select instance_name from v$instance; will give you SID name. select name from v$database; will give DB NAME. select instance_name from v$instance; will give you SID name.
I a similar scenario, I was able to connect to the database by using cx_Oracle.makedsn()
to create a dsn string with a given SID
(instead of the service name):
dsnStr = cx_Oracle.makedsn("oracle.sub.example.com", "1521", "ora1")
This returns something like
(DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=oracle.sub.example.com)(PORT=1521)))(CONNECT_DATA=(SID=ora1)))
which can then be used with cx_Oracle.connect()
to connect to the database:
con = cx_Oracle.connect(user="myuser", password="mypass", dsn=dsnStr) print con.version con.close()
For those looking for how to specify service_name instead of SID.
From changelog for SQLAlchemy 1.0.0b1 (released on March 13, 2015):
[oracle] [feature] Added support for cx_oracle connections to a specific service name, as opposed to a tns name, by passing
?service_name=<name>
to the URL. Pull request courtesy Sławomir Ehlert.
The change introduces new, Oracle dialect specific option service_name
which can be used to build connect string like this:
from sqlalchemy import create_engine from sqlalchemy.engine import url connect_url = url.URL( 'oracle+cx_oracle', username='some_username', password='some_password', host='some_host', port='some_port', query=dict(service_name='some_oracle_service_name')) engine = create_engine(connect_url)
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