I am looking for iterator to infinitely iterate collection in a loop mode. So that when end index of collection is reached, then iterator should return element at start index.
The following solution seems working, but I hope it can be made in a better way.
public struct LoopIterator<T: Collection>: IteratorProtocol {
private let collection: T
private var startIndexOffset: T.IndexDistance
public init(collection: T) {
self.collection = collection
startIndexOffset = 0
}
public mutating func next() -> T.Iterator.Element? {
guard !collection.isEmpty else {
return nil
}
let index = collection.index(collection.startIndex, offsetBy: startIndexOffset)
startIndexOffset += T.IndexDistance(1)
if startIndexOffset >= collection.count {
startIndexOffset = 0
}
return collection[index]
}
}
extension Array {
func makeLoopIterator() -> LoopIterator<Array> {
return LoopIterator(collection: self)
}
}
// Testing...
// Will print: 1, 2, 3, 1, 2, 3
var it = [1, 2, 3].makeLoopIterator()
for _ in 0..<6 {
print(it.next())
}
Is it a right way to do custom iterator? What can be improved?
Thanks!
In Swift 3 (which you're using), indexes are intended to be advanced by the collection itself. With that, you can simplify this as follows:
public struct LoopIterator<Base: Collection>: IteratorProtocol {
private let collection: Base
private var index: Base.Index
public init(collection: Base) {
self.collection = collection
self.index = collection.startIndex
}
public mutating func next() -> Base.Iterator.Element? {
guard !collection.isEmpty else {
return nil
}
let result = collection[index]
collection.formIndex(after: &index) // (*) See discussion below
if index == collection.endIndex {
index = collection.startIndex
}
return result
}
}
Now we simply move the index forward, and if it now points to the end, reset it to the beginning. No need for count
or IndexDistance
.
Note that I've used formIndex
here, which exists to improve performance in somewhat obscure cases (specifically around AnyIndex
) since your Iterator works on any Collection (and therefore any Index). The simpler version would be index = collection.index(after: index)
, and that may be better in most cases.
For all the gory details on Swift 3 indices, see SE-0065.
With Swift 5, you can use one of the following examples in order to solve your problem.
AnyIterator
As an alternative to creating a new type that conforms to IteratorProtocol
, you can use AnyIterator
. The following code, based on Rob Napier's answer, shows how to use it:
extension Array {
func makeInfiniteLoopIterator() -> AnyIterator<Element> {
var index = self.startIndex
return AnyIterator({
if self.isEmpty {
return nil
}
let result = self[index]
index = self.index(after: index)
if index == self.endIndex {
index = self.startIndex
}
return result
})
}
}
Usage:
let infiniteLoopIterator = [1, 2, 3].makeInfiniteLoopIterator()
for val in infiniteLoopIterator.prefix(5) {
print(val)
}
/*
prints:
1
2
3
1
2
*/
let infiniteLoopIterator = [1, 2, 3].makeInfiniteLoopIterator()
let array = Array(infiniteLoopIterator.prefix(7))
print(array) // prints: [1, 2, 3, 1, 2, 3, 1]
let infiniteLoopIterator = [1, 2, 3].makeInfiniteLoopIterator()
let val1 = infiniteLoopIterator.next()
let val2 = infiniteLoopIterator.next()
let val3 = infiniteLoopIterator.next()
let val4 = infiniteLoopIterator.next()
print(String(describing: val1)) // prints: Optional(1)
print(String(describing: val2)) // prints: Optional(2)
print(String(describing: val3)) // prints: Optional(3)
print(String(describing: val4)) // prints: Optional(1)
AnySequence
A similar approach is to use AnySequence
:
extension Array {
func makeInfiniteSequence() -> AnySequence<Element> {
return AnySequence({ () -> AnyIterator<Element> in
var index = self.startIndex
return AnyIterator({
if self.isEmpty {
return nil
}
let result = self[index]
self.formIndex(after: &index) // alternative to: index = self.index(after: index)
if index == self.endIndex {
index = self.startIndex
}
return result
})
})
}
}
Usage:
let infiniteSequence = [1, 2, 3].makeInfiniteSequence()
for val in infiniteSequence.prefix(5) {
print(val)
}
/*
prints:
1
2
3
1
2
*/
let infiniteSequence = [1, 2, 3].makeInfiniteSequence()
let array = Array(infiniteSequence.prefix(7))
print(array) // prints: [1, 2, 3, 1, 2, 3, 1]
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