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Can anyone tell me if I can (in the command line) issue a POST command that contains a file and other parameters?
I am trying to do something like:
curl -X POST -F "key=myKey&[email protected]" http://localhost:8080/myRestService/
I am really new in this domain, so excuse me for my basic question. But it does not seems to work well. Any suggestion? Tank you very much
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Windows user running curl binaries should use double-quotes instead of single quotes to get multiple query parameters command working.
Users can send data with the POST request using the -d flag. The following POST request sends a user and a pass field along with their corresponding values. POSTing with curl's -d option will include a default header that looks like: Content-Type: application/x-www-form-urlencoded .
To post JSON data using Curl, you need to set the Content-Type of your request to application/json and pass the JSON data with the -d command line parameter. The JSON content type is set using the -H "Content-Type: application/json" command line parameter. JSON data is passed as a string.
You can pass the body of the POST message to Curl with the -d or --data command-line option. Curl will send data to the server in the same format as the browser when submitting an HTML form. To send binary data in the body of a POST message with Curl, use the --data-binary command-line option.
You should use -d param
check a man page http://curl.haxx.se/docs/manpage.html
If you start the data with the letter @, the rest should be a file name to read the data from, or - if you want curl to read the data from stdin. The contents of the file must already be URL-encoded. Multiple files can also be specified. Posting data from a file named 'foobar' would thus be done with --data @foobar.
Try to specify a full path to your file.
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