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cudaMemcpyToSymbol vs. cudaMemcpy why is it still around (cudaMemcpyToSymbol)

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cuda

As stated by other questions and according to the link, you can no longer use the symbol name for this function. Now that the feature is gone, when would ever want to use this over cudaMemCpy? When would you ever want to use it at all? What is the tradeoff or benefit?

https://docs.nvidia.com/cuda/cuda-runtime-api/group__CUDART__MEMORY.html#group__CUDART__MEMORY_1g9bcf02b53644eee2bef9983d807084c7

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rubixibuc Avatar asked Apr 13 '13 06:04

rubixibuc


1 Answers

In short, because cudaMemcpy can't do the same thing as cudaMemcpyToSymbol without an additional API call. Consider a constant memory array:

__constant__ float coeffs[8];

To copy values to this array using cudaMemcpyToSymbol, just do

cudaMemcpyToSymbol(coeffs, hostData, 8*sizeof(float));

To do the same with cudaMemcpy requires this:

float *dcoeffs;
cudaGetSymbolAddress((void **)&dcoeffs, coeffs);
cudaMemcpy(dcoeffs, hostData, 8*sizeof(float), cudaMemcpyHostToDevice);

A direct call to cudaMemcpy is illegal without prior symbol lookup.

[standard disclaimer: all code written in browser without access to documentation or compiler, use at own risk]

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talonmies Avatar answered Oct 23 '22 15:10

talonmies