Menu
I'm using CSS3 and RGBA to create a white-to-transparent gradient:
div {
background-image: -moz-linear-gradient(left, rgba(255, 255, 255, 1), rgba(0, 0, 0, 0));
background-image: -ms-linear-gradient(left, rgba(255, 255, 255, 1), rgba(0, 0, 0, 0));
background-image: -webkit-gradient(linear, 0 0, 100% 0, from(rgba(255, 255, 255, 1)), to(rgba(0, 0, 0, 0)));
background-image: -webkit-linear-gradient(left, rgba(255, 255, 255, 1), rgba(0, 0, 0, 0));
background-image: -o-linear-gradient(left, rgba(255, 255, 255, 1), rgba(0, 0, 0, 0));
background-image: linear-gradient(left, rgba(255, 255, 255, 1), rgba(0, 0, 0, 0));
background-repeat: repeat-x;
filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='rgba(255, 255, 255, 1)', endColorstr='rgba(0, 0, 0, 0)', GradientType=1);
padding: 2rem 0;
}
Fiddle here: http://jsfiddle.net/alecrust/fYz45/
However as you'll notice, the gradient is dark in the middle. I'm getting this:
And I'm expecting this:
How can I rectify?
524
To add transparency, we use the rgba() function to define the color stops. The last parameter in the rgba() function can be a value from 0 to 1, and it defines the transparency of the color: 0 indicates full transparency, 1 indicates full color (no transparency).
First, -webkit-gradient uses a two-point syntax that lets you explicitly state where a linear gradient starts and ends. linear-gradient does away with this in favor of convenient box-filling behavior. If you really want the gradient to stop before the edges of the box, you can do so via color stop placement.
Change your final step to #FFFFFF00 (rgba(255, 255, 255, 0)) instead of #00000000:
http://jsfiddle.net/fYz45/6/
84
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
