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I'm trying to stripe the colours of alternating elements. But I want the row colors to alternate only the visible rows. If you have a look at the below here is my attempt at trying to get it working.
http://jsfiddle.net/kuwFp/3/
<!DOCTYPE html>
<html>
<head>
<style>
p:not(.hide):nth-child(odd)
{
background:#ff0000;
}
p:not(.hide):nth-child(even)
{
background:#0000ff;
}
.hide { display:none; }
</style>
</head>
<body>
<p>The first paragraph.</p>
<p class="hide">The second paragraph.</p>
<p>The third paragraph.</p>
</body>
</html>
712
Tap into the tr (table row) element is CSS. Use the nth-child() selector and add background-color of your choice to all odd (or even) table rows.
Use “tr: odd” to select the odd data & use “tr: even” to select the even data in the row.
You can't do this with pure CSS because the :nth-child selector is calculated with respect to the element and :not does not filter element position in the DOM. You need to use JavaScript for a fully flexible solution.
It's still possible for you to do this inflexibly by making elements after .hide with :nth-child alternate the color they should be:
.hide + p:nth-child(odd) {
background: #0000ff;
}
You can continue to add similar rules for more and more combinations of sibling .hide and p, but this is very inflexible.
136
The trick is to hide a row with different tag, not class. In my example I use "del" tag to hide.
.list div:nth-of-type(odd) { background: ghostwhite; }
.list del { display: none; }<div class="list">
<div>1</div>
<div>2</div>
<div>3</div>
<del>4</del>
<div>5</div>
<del>6</del>
<div>7</div>
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