I'm encrypting a string in a web application using CryptoJS (v 2.3), and I need to decrypt it on the server in Python, so I'm using PyCrypto. I feel like I'm missing something because I can't can it working.
Here's the JS:
Crypto.AES.encrypt('1234567890123456', '1234567890123456',
{mode: new Crypto.mode.CBC(Crypto.pad.ZeroPadding)})
// output: "wRbCMWcWbDTmgXKCjQ3Pd//aRasZ4mQr57DgTfIvRYE="
The python:
from Crypto.Cipher import AES
import base64
decryptor = AES.new('1234567890123456', AES.MODE_CBC)
decryptor.decrypt(base64.b64decode("wRbCMWcWbDTmgXKCjQ3Pd//aRasZ4mQr57DgTfIvRYE="))
# output: '\xd0\xc2\x1ew\xbb\xf1\xf2\x9a\xb9\xb6\xdc\x15l\xe7\xf3\xfa\xed\xe4\xf5j\x826\xde(m\xdf\xdc_\x9e\xd3\xb1'
Here is a version with CryptoJS 3.1.2. Always beware of the following things (use the same in both languages):
If a string is passed as the key
argument to the CryptoJS encrypt()
function, the string is used to derive the actual key to be used for encryption. If you wish to use a key (valid sizes are 16, 24 and 32 byte), then you need to pass it as a WordArray.
The result of the CryptoJS encryption is an OpenSSL formatted ciphertext string. To get the actual ciphertext from it, you need to access the ciphertext
property on it.
The IV must be random for each encryption so that it is semantically secure. That way attackers cannot say whether the same plaintext that was encrypted multiple times is actually the same plaintext when only looking at the ciphertext.
Below is an example that I have made.
JavaScript:
var key = CryptoJS.enc.Utf8.parse('1234567890123456'); // TODO change to something with more entropy
function encrypt(msgString, key) {
// msgString is expected to be Utf8 encoded
var iv = CryptoJS.lib.WordArray.random(16);
var encrypted = CryptoJS.AES.encrypt(msgString, key, {
iv: iv
});
return iv.concat(encrypted.ciphertext).toString(CryptoJS.enc.Base64);
}
function decrypt(ciphertextStr, key) {
var ciphertext = CryptoJS.enc.Base64.parse(ciphertextStr);
// split IV and ciphertext
var iv = ciphertext.clone();
iv.sigBytes = 16;
iv.clamp();
ciphertext.words.splice(0, 4); // delete 4 words = 16 bytes
ciphertext.sigBytes -= 16;
// decryption
var decrypted = CryptoJS.AES.decrypt({ciphertext: ciphertext}, key, {
iv: iv
});
return decrypted.toString(CryptoJS.enc.Utf8);
}
Python 2 code with pycrypto:
BLOCK_SIZE = 16
key = b"1234567890123456" # TODO change to something with more entropy
def pad(data):
length = BLOCK_SIZE - (len(data) % BLOCK_SIZE)
return data + chr(length)*length
def unpad(data):
return data[:-ord(data[-1])]
def encrypt(message, key):
IV = Random.new().read(BLOCK_SIZE)
aes = AES.new(key, AES.MODE_CBC, IV)
return base64.b64encode(IV + aes.encrypt(pad(message)))
def decrypt(encrypted, key):
encrypted = base64.b64decode(encrypted)
IV = encrypted[:BLOCK_SIZE]
aes = AES.new(key, AES.MODE_CBC, IV)
return unpad(aes.decrypt(encrypted[BLOCK_SIZE:]))
Warning: Keep in mind that both python2 and pycrypto are obsolete, so the code has to be adjusted to fit python3 and pycryptodome.
Other considerations:
It seems that you want to use a passphrase as a key. Passphrases are usually human readable, but keys are not. You can derive a key from a passphrase with functions such as PBKDF2, bcrypt or scrypt.
The code above is not fully secure, because it lacks authentication. Unauthenticated ciphertexts may lead to viable attacks and unnoticed data manipulation. Usually the an encrypt-then-MAC scheme is employed with a good MAC function such as HMAC-SHA256.
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