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Cross-regional decimal/double parsing

As a matter of fact, I have multiple systems that can generate numeric data and they are stored on some web server in text files. Some of the systems use decimal point as fraction separator, some of the systems use decimal comma as same.

Applications (fat client, .net 2.0) can also be run on either kind of systems.

So after some stumbling I did this: ( http://pastebin.com/vhLXABDD )

    public static bool HasDecimalComma;
    public static bool HasDecimalPeriod;

    public static double GetNumber(string NumberString)
    {
        if (!HasDecimalComma && !HasDecimalPeriod)
        {
            string s = string.Format("{0:0.0}", 123.123);
            if (s.Contains('.'))
            {
                HasDecimalPeriod = true;
            }
            else if (s.Contains(','))
            {
                HasDecimalComma = true;
            }
            else
            {
                throw new SystemException(string.Format("strange number format '{0}'", s));
            }
        }
        if (HasDecimalComma)
        {
            return double.Parse(NumberString.Replace('.', ','));
        }
        if (HasDecimalPeriod)
        {
            return double.Parse(NumberString.Replace(',', '.'));
        }
        throw new ArgumentException(string.Format("can't parse '{0}'", NumberString));
    }

Would you suggest any better, more elegant way?

EDIT:

I am sorry for not mentioning it before, and since your answers lean in that direction - I can't store generating culture with the numbers, I can only try to 'detect' it.

like image 879
Daniel Mošmondor Avatar asked Oct 03 '22 01:10

Daniel Mošmondor


2 Answers

Try with this:

    static double GetDouble(string s)
    {
        double d;

        var formatinfo = new NumberFormatInfo();

        formatinfo.NumberDecimalSeparator = ".";

        if (double.TryParse(s, NumberStyles.Float, formatinfo, out d))
        {
            return d;
        }

        formatinfo.NumberDecimalSeparator = ",";

        if (double.TryParse(s, NumberStyles.Float, formatinfo, out d))
        {
            return d;
        }

        throw new SystemException(string.Format("strange number format '{0}'", s));
    }
like image 89
Alessandro D'Andria Avatar answered Oct 13 '22 09:10

Alessandro D'Andria


If you are unable to change the call site, and you guarantee that no other kind of separator will be present beside the decimal separator, then you can, more or less use your method. I would suggest

  1. Мoving the HasDecimalComma and HasDecimalPeriod to the body of the method - global state is absolutely not necessary in this case.
  2. Using TryParse instead of Parse, because the numbers are expected to be potentially faulty.
  3. Explitly specifying the InvariantCulture culture (it has a decimal period).
  4. Allowing for number that have neither comma nor period, since "3" is a floating point number after all.

So something along these lines:

///comment the method assumptions here
///otherwise the method might seem wrong
public static double GetNumber(string numberString)
{
   bool hasDecimalComma = numberString.Contains(',');
   if (hasDecimalComma)
     numberString = numberString.Replace(',', '.')
   double result;
   bool success = double.TryParse(numberString, 
                      NumberStyles.Float, 
                      CultureInfo.InvariantCulture,
                      out result);
   if (success)
     return result;
   else 
     throw new ArgumentException(
                           string.Format("can't parse '{0}'", numberString));
}

(Old answer, good in principle, impossible in practice)

I would suggest storing the generating culture along the string, and then using it to call the method, along these lines (using double.TryParse):

public static double GetNumber(string numberString, CultureInfo culture)
{
   double result;
   bool success = double.TryParse(numberString, 
                          NumberStyles.Float | NumberStyles.AllowThousands, 
                          culture,
                          out result);
   if (success)
      return result;
   else 
      throw new ArgumentException(
                               string.Format("can't parse '{0}'", numberString));
}
like image 31
SWeko Avatar answered Oct 13 '22 10:10

SWeko