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Cron Job sixth parameter in Java

Tags:

java

cron

crontab

I am very new to Java. As my first project, I am going to work with cron job scheduler. I want some clarification on scheduling. I have a code which will run every hour.

  CronTrigger ct = new CronTrigger("cronTrigger", "group2", "0 1/0 * * * ?"); 

I have read the documents about scheduling, but I got confused

In one document i have read like in the below

 ("0 0 * * * ?") 
  • 1st 0 indicates seconds
  • 2nd indicates mins
  • 3rd hour
  • 4th which day of the month
  • 5th which month.

In some document I read that 1st indicates mins 2nd - hour etc.

Can anyone please explain me this(0 1/0 * * * ?) and also what it means (1/0)?

And I want to run a job in every six hours.

If i give like this (0 */6 * * * ?) whether it will run in every six hours?

like image 292
Priya Avatar asked Apr 29 '16 05:04

Priya


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1 Answers

If you check in crontab.guru, both of these are almost equivalent:

*   * * * *
* 1/0 * * *

This is because X/Y means: starting from X, every Y. That is, all X + Yn. So if you say */2 it will do every 2 hours.

In this case: 1/0 means "starting from 1, every hour", so it matches from 1 to 23, whereas * matches from 0 to 23.

Following your question, */6 matches every 6 hour, so it will precisely run at hour 0, 6, 12 and 18.

Regarding your question on what is the 6th parameter ? doing, I read that:

I believe that's processed by the CronExpression class which has six constants: minute, hour, day, month, weekday, year. Cron uses minute, hour, day, month, weekday. The addition of the year for the yearly() method seems to be the reason for the extra *.

So instead of having the common syntax

 +---------------- minute (0 - 59)
 |  +------------- hour (0 - 23)
 |  |  +---------- day of month (1 - 31)
 |  |  |  +------- month (1 - 12)
 |  |  |  |  +---- day of week (0 - 6) (Sunday=0 or 7)
 |  |  |  |  |
 *  *  *  *  *  command to be executed 

With Java you have

   +----------------- minute (0 - 59)
   |  +-------------- hour (0 - 23)
   |  |  +----------- day of month (1 - 31)
   |  |  |  +-------- month (1 - 12)
   |  |  |  |  +----- day of week (0 - 6) (Sunday=0 or 7)
 # |  |  |  |  |  +-- year                       <-- this is extra !!
   |  |  |  |  |  |
   *  *  *  *  *  * command to be executed 

This last parameter can have a value as well, but in your case it specifies ?. As for what I read in crontab.guru, it means:

? blank (non-standard)

So I would schedule it normally with the 5 usual parameters and then add ? at the end so that it runs in all years.

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fedorqui 'SO stop harming' Avatar answered Oct 06 '22 21:10

fedorqui 'SO stop harming'